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GRE Math Challenge #102- Value of(2^1^0 - 2^9 )(2^8 - 2^7 )
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09 May 2015, 12:05
09 May 2015, 12:05
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Question Stats:
79% (01:03) correct
20% (01:46) wrong based on 39 sessions
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\((2^{10} - 2^9 )(2^8 - 2^7 ) =\)
(A) \(2\)
(B) \(2^2\)
(C) \(2^4\)
(D) \(2^8\)
(E) \(2^{16}\)
(A) \(2\)
(B) \(2^2\)
(C) \(2^4\)
(D) \(2^8\)
(E) \(2^{16}\)
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GRE Math Challenge #102- Value of(2^1^0 - 2^9 )(2^8 - 2^7 )
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31 Jan 2020, 07:19
31 Jan 2020, 07:19
1
sandy wrote:
\((2^{10} - 2^9 )(2^8 - 2^7 ) =\)
(A) \(2\)
(B) \(2^2\)
(C) \(2^4\)
(D) \(2^8\)
(E) \(2^{16}\)
(A) \(2\)
(B) \(2^2\)
(C) \(2^4\)
(D) \(2^8\)
(E) \(2^{16}\)
Let's do a bit of factoring...
\(2^{10}-2^9=2^9(2^1-1)=2^9(2-1)=2^9\)
\(2^{8}-2^7=2^7(2^1-1)=2^7(2-1)=2^7\)
So, \((2^{10} - 2^9 )(2^8 - 2^7 ) = (2^9)(2^7) = 2^{16}\)
Answer: E
RELATED VIDEO
Re: GRE Math Challenge #102- Value of(2^1^0 - 2^9 )(2^8 - 2^7 )
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15 Feb 2023, 11:40
15 Feb 2023, 11:40
Hi Brent GreenlightTestPrep, to clarify is it correct to use FOIL method here? though the calculation will be quite messy. Thanks
