Bunuel wrote:
How many different 3-digit numbers are greater than 299 and do not contain the digits 1, 6, or 8?
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We have to consider nos from 300 to 999
Now the first digit from right - it has to start from 3 since it is greater than 299
Therefore the first digit can start with: 3, 4, 5, 7, 9 (total of 5 option)
The second digit can be: 0, 2, 3, 4, 5, 7, 9 (total of 7 options)
The third digit can be: 0, 2, 3, 4, 5, 7, 9 (total of 7 options)
Therefore total no. of ways we have = 5 * 7 * 7 = 245 ways
(More over here it has asked for different three digit number and not different digits so we can consider the 333, 444, 555,666,777,888 and 999 as they all are different numbers)