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How To Solve: Probability Problems involving Coin Toss
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Updated on: 11 Jan 2023, 01:51
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This is part of our GRE Math Essentials project&GRE Math Essentials - A most comprehensive handout!!! that are the best complement to our GRE Math Book. It provides a cutting-edge, in-depth overview of all the math concepts from basic to mid-upper levels. The book still remains our hallmark: from basic to the most advanced GRE math concepts tested during the exam. Moreover, the following chapters will give you many tips, tricks, and shortcuts to make your quant preparation more robust and solid.
Show: :: DOWNLOAD PDF: How To Solve: Probability Problems involving Coin Toss
• Probability of Getting 0 Head, P(0H) = \(\frac{1}{8}\) (As there is ONLY one outcome out of 8 where we get 0 Head or 3 Tails)
• Probability of Getting 1 Head, P(1H) = \(\frac{3}{8}\) (As there are three outcomes out of 8 where we get 1 Head i.e. HTT, THT, TTH) We can also find this by finding the position of that one Head out of three slots in 3C1 = \(\frac{3!}{1!*2!}\) = 3 ways and divide it by the total number of outcomes which is 8
• Probability of Getting 2 Head, P(2H) = \(\frac{3}{8}\) (As there are three outcomes out of 8 where we get 2 Heads i.e. HHT, THH, HTH) We can also find this by finding the position of those 2 Heads or 1 Tail out of three slots in 3C2 = \(\frac{3!}{2!*1!}\) = 3 ways and divide it by the total number of outcomes which is 8
• Probability of Getting 3 Head, P(3H) = \(\frac{1}{8}\) (As there is ONLY one outcome out of 8 where we get 3 Head i.e. HHH)
• Probability of Getting 0 Tail, P(0T) = \(\frac{1}{8}\) (As there is ONLY one outcome out of 8 where we get 0 Tail or 3 Heads)
• Probability of Getting 1 Tail, P(1T) = \(\frac{3}{8}\) (As there are three outcomes out of 8 where we get 1 Tail i.e. THH, HTH, HHT) We can also find this by finding the position of that one Tail out of three slots in 3C1 = \(\frac{3!}{1!*2!}\) = 3 ways and divide it by the total number of outcomes which is 8
• Probability of Getting 2 Tail, P(2T) = \(\frac{3}{8}\) (As there are three outcomes out of 8 where we get 2 Tails i.e. TTH, THT, HTT) We can also find this by finding the position of those 2 Tails or 1 Head out of three slots in 3C2 = \(\frac{3!}{2!*1!}\) = 3 ways and divide it by the total number of outcomes which is 8
• Probability of Getting 3 Tail, P(3T) = \(\frac{1}{8}\) (As there is ONLY one outcome out of 8 where we get 3 Tail i.e. TTT)