Carcass wrote:
If 3y + 5 = 7x, then 21y – 49x =
(A) –40
(B) –35
(C) –10
(D) 0
(E) 15
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITIONGRE - Math BookGiven: 3y + 5 = 7x
Subtract 5 from both sides to get: 3y = 7x - 5
Subtract 7x from both sides to get:
3y - 7x = -5ASIDE: Why did I rewrite the given equation like that?
Well, since we want to find the value of 21y – 49x, I thought it might be useful to rewrite the given equation in the same form (something times y - something times x)
We want to find the value of 21y – 49x
Notice that we can factor this expression to get: 21y – 49x = 7(
3y - 7x)
= 7(
-5)
[since we already determined that 3y - 7x = -5]= -35
Answer: B
Cheers,
Brent