Carcass wrote:
If \(a + \frac{1}{a} = 4\) then what is the value of \(a^2 + \frac{1}{a^2}\) ?
A. 12
B. 14
C. 16
D. 18
E. 20
Strategy: When I compare the two given expressions, I recognize that \(a^2\) is the square of \(a\), and \(\frac{1}{a^2}\) is the square of \(\frac{1}{a}\).
So, let's see what happens if we take the given equation, \(a + \frac{1}{a} = 4\), and square both sides. We get: \((a + \frac{1}{a})^2 = 4^2\)
Use FOIL to expand the left side: \(a^2 + 1 + 1 + \frac{1}{a^2} = 16\)
Simplify: \(a^2 + 2 + \frac{1}{a^2} = 16\)
Subtract \(2\) from both sides of the equation: \(a^2 + \frac{1}{a^2} = 14\)
Answer: B