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If a regular polygon has x angles each measuring q degrees,
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07 May 2020, 10:29
07 May 2020, 10:29
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If a regular polygon has x angles each measuring q degrees, then what is the value of q ?
A. \(\frac{180(x-3)}{x}\)
B. \(180(x-3) + 180\)
C. \(\frac{30x+180}{x}\)
D. \(\frac{180(x-2)}{x}\)
E. \(\frac{360}{x} -10x\)
Kudos for the right answer and explanation
A. \(\frac{180(x-3)}{x}\)
B. \(180(x-3) + 180\)
C. \(\frac{30x+180}{x}\)
D. \(\frac{180(x-2)}{x}\)
E. \(\frac{360}{x} -10x\)
Kudos for the right answer and explanation
Re: If a regular polygon has x angles each measuring q degrees,
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07 May 2020, 22:12
07 May 2020, 22:12
1
1
For any polygon, sum of interior angles is 180(n-2), where n is the number of angles.
To find out the individual angles, we need to divide number of angles with the product of 180(n-2).
Thus, final equation becomes, 180(n-2) / n.
Example: Consider a triangle, it has 3 sides, 180 (3-2) = 180. Thus sum of interior angles of triangle is 180. To find the individual angles, 180/ 3 = 60.
Hence, for the given question, substitute x instead of n. The answer is D.
To find out the individual angles, we need to divide number of angles with the product of 180(n-2).
Thus, final equation becomes, 180(n-2) / n.
Example: Consider a triangle, it has 3 sides, 180 (3-2) = 180. Thus sum of interior angles of triangle is 180. To find the individual angles, 180/ 3 = 60.
Hence, for the given question, substitute x instead of n. The answer is D.
Re: If a regular polygon has x angles each measuring q degrees,
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08 May 2020, 07:07
08 May 2020, 07:07
1
we know internal angles of regular polygon is given by : (n-2)*180 /n where n = the number of sides
Also the number of internal angles= number of side : take a triangle for example
we are given this equation is =q
so q=(n-2)*180 /n and n=x
so D
Also the number of internal angles= number of side : take a triangle for example
we are given this equation is =q
so q=(n-2)*180 /n and n=x
so D
