\(2x+3y=180\)
factor of 20 should be distributed to LHS and RHS (left and right hand sides) of the above expression, rewritten as \(2x+2y=180-y\), \(x+y=90-y/2\). Notice that x and y are still divisible by 20, but 90 is not divisible by 20. For 90 to be divisible by 20, it must be reduced to either 80, 60, 40 or 20
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Let's pick 80 as RHS value of \(x+y=90-y/2\), then \(90-y/2=80\) and y=20
When y=20 along with \(x+y=80\), x=60. Hence, x=60 and y=20
**
If we pick 60 as nextRHS value of \(x+y=90-y/2\), then \(90-y/2=60\) and y=60
When y=60 along with \(x+y=60\), x=0. Hence, x=0 and y=60
REJECT**
Answer is
CNote: the additional solution between two up and down stars helps if the question is conversed into QC type.
Carcass wrote:
If ABC is a straight line as shown in the figure below, and the angles x & y are integer multiples of 20, what is the value of x?
Attachment:
screenshot.124.jpg
A. 20
B. 40
C. 60
d. 80
E. 100
Source:
manhattanreview