Carcass wrote:
If an integer greater than 100 and less than 1,000 is to be selected at random, what is the probability that the integer selected will be a multiple of 7?
A. \(\frac{142}{999}\)
B. \(\frac{142}{900}\)
C. \(\frac{142}{899}\)
D. \(\frac{128}{900}\)
E. \(\frac{128}{899}\)
Kudos for the right answer and explanation
We should start by asking "How many integers are greater than 100 and less than 1000?"
And other words, "How many integers are there from 101 to 999 inclusive?"
A nice rule says:
the number of integers from x to y inclusive equals y - x + 1So, the number of integers from 101 to 999 inclusive = 999 - 101 + 1 = 899
So, we are randomly selecting one number from 899 integers
This tells us that the denominator of the probability must be 899
So we can eliminate answer choices A, B and D
We are left with answer choice C (142/899) and answer choice E (128/899)
Since the numerators are quite
spread apart we can use some
estimation.
There are 899 integers to choose from, and approximately 1/7 of those integers are multiples of 7
1/7 of 899 ≈ 128.4
So among the
899 integers, approximately
128 of them are multiples of 7.
So, P(select a multiple of 7) ≈
128/
899So, the correct answer must be E
Cheers,
Brent