Carcass wrote:
If p and q represent nonzero single-digit values in the correctly worked addition problem above, what is the value of q + p?
(A) 2
(B) 4
(C) 6
(D) 8
(E) 20
First add the column of units digits to get: 6 + 7 + 8 =
21
So, we carry the
2 so that it's included in the sum of the tens digits.
From here, we can see that the sum of the tens digits has units digit 1.
That is, 2 + 3 + 2 + q = ?
1In other words, 7 + q = ?
1So, it must be the case that
q = 4, which means the sum of the tens digits =
11.
So, we carry the
1 so that it's included in the sum of hundreds digits.
Finally, we can see that the sum of the hundreds digits is 9.
In other words, 1 + p + 5 + 1 = 9
Solve to get:
p = 2At this point, we can confirm our values by adding the three numbers to get a sum of 911.
This means q + p =
4 +
2 =
6Answer: C