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If s is the sum of consecutive even integers w, x, y, and z, where w <
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15 Sep 2021, 01:15
15 Sep 2021, 01:15
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85% (01:30) correct
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If s is the sum of consecutive even integers w, x, y, and z, where w < x < y < z, all of the following must be true EXCEPT
(A) z − w = 3(y − x)
(B) s is divisible by 8
(C) The average of w, x, y, and z is odd
(D) s is divisible by 4
(E) w + x + 8 = y + z
(A) z − w = 3(y − x)
(B) s is divisible by 8
(C) The average of w, x, y, and z is odd
(D) s is divisible by 4
(E) w + x + 8 = y + z
Re: If s is the sum of consecutive even integers w, x, y, and z, where w <
[#permalink]
15 Sep 2021, 11:38
15 Sep 2021, 11:38
1
Not sure this is the fastest way,
Given 4 consecutive even integers w, x, y, and z, where w < x < y < z, Let them be a-3,a-1,a+1 and a+3.
which means a will be a odd number.
So substitute in the following choices.
(A) z − w = 3(y − x) => a + 3 - a + 3 = 3 (a+1-a+1) - True
(B) s is divisible by 8 => sum = 4a divisible by 8 - Cannot be always true
(C) The average of w, x, y, and z is odd => this is obvious - True
(D) s is divisible by 4 - Sum = 4a - True
(E) w + x + 8 = y + z = a-3 + a-1 + 8 = a+1 +a+3 - True
Answer is B
Given 4 consecutive even integers w, x, y, and z, where w < x < y < z, Let them be a-3,a-1,a+1 and a+3.
which means a will be a odd number.
So substitute in the following choices.
(A) z − w = 3(y − x) => a + 3 - a + 3 = 3 (a+1-a+1) - True
(B) s is divisible by 8 => sum = 4a divisible by 8 - Cannot be always true
(C) The average of w, x, y, and z is odd => this is obvious - True
(D) s is divisible by 4 - Sum = 4a - True
(E) w + x + 8 = y + z = a-3 + a-1 + 8 = a+1 +a+3 - True
Answer is B
gmatclubot
Re: If s is the sum of consecutive even integers w, x, y, and z, where w < [#permalink]
15 Sep 2021, 11:38
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