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If the average (arithmetic mean) of k and k + 5 is b and if th
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09 Jul 2021, 06:49
2
Theory
โก Average = Sum of all the Values / Total Number of Values โก Sum of All the values = Average * Total Number of Values
If the average (arithmetic mean) of ๐ and ๐ + 5 is ๐ => k + (k+5) = b * 2 [As there are 2 values] => 2k + 5 = 2b => b = \(\frac{2k+5}{2}\) = k + \(\frac{5}{2}\)
If the average of ๐ and ๐ โ 9 is ๐ => k + (k-9) = c * 2 [As there are 2 values] => 2k - 9 = 2c => c = \(\frac{2k-9}{2}\) = k - \(\frac{9}{2}\)
What is the average of ๐ and ๐ Average of b and c = \(\frac{b+c}{2}\) = (\(\frac{1}{2})\)*(k + \(\frac{5}{2}\) + k - \(\frac{9}{2}\)) = (\(\frac{1}{2})\)*(2k - \(\frac{4}{2}\)) = (\(\frac{1}{2})\)*(2k - 2) = k - 1
So, Answer will be B Hope it helps!
To learn more about Statistics watch the following video
gmatclubot
If the average (arithmetic mean) of k and k + 5 is b and if th [#permalink]