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If the graph y = 2x2 - 2 intersects line k at (t, 4) and (p, 0), what
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21 Feb 2022, 07:30
21 Feb 2022, 07:30
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50% (02:25) correct
50% (02:11) wrong based on 10 sessions
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If the graph \(y = 2x^2 - 2\) intersects line k at (t, 4) and (p, 0), what is the greatest possible value of the slope of k?
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If the graph y = 2x2 - 2 intersects line k at (t, 4) and (p, 0), what
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04 Mar 2022, 23:29
04 Mar 2022, 23:29
1
Carcass wrote:
If the graph \(y = 2x^2 - 2\) intersects line k at (t, 4) and (p, 0), what is the greatest possible value of the slope of k?
Show: ::
2
Plug \(x = t\) and \(y = 4\) in \(y = 2x^2 - 2\)
\(4 = 2t^2 - 2\)
\(2t^2 = 6\)
\(t^2 = 3\)
\(t = ±\sqrt{3}\)
Now, Plug \(x = p\) and \(y = 0\) in \(y = 2x^2 - 2\)
\(0 = 2p^2 - 2\)
\(2p^2 = 2\)
\(p^2 = 1\)
\(p = ±1\)
(Refer to the figure below)
Greatest possible value of slope would be given when the line k passes through (\(\sqrt{3}\), 4) and (1, 0)
m = \(\frac{(4 - 0)}{(\sqrt{3} - 1)} = \frac{4}{0.732} = 5.46\)
Attachment:
Max slope of line k.png [ 42.51 KiB | Viewed 2370 times ]
General Discussion
Re: If the graph y = 2x2 - 2 intersects line k at (t, 4) and (p, 0), what
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03 Apr 2022, 19:23
03 Apr 2022, 19:23
1
Hi. How is the answer 2? Can you provide an explanation arriving at that answer
