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If the integer x is divisible by 3 but not by
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11 Jul 2018, 07:36
11 Jul 2018, 07:36
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Question Stats:
78% (00:41) correct
21% (00:45) wrong based on 19 sessions
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If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
Re: If the integer x is divisible by 3 but not by
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11 Jul 2018, 10:53
11 Jul 2018, 10:53
1
amorphous wrote:
If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
Here,
As the question tells us that x is not divisible by 2 then we have to look the denominator any even value divisible by 2 will give the answer.
But here we are left with 2 option. Option A and Option E
In option A , the number \(\frac{x+1}{2}\) will be divisible by 2, since the numerator: x + 1 = Even number (since x is odd, so Odd + 1 = even number and it will be divisible by 2)
So we are left with option E
Re: If the integer x is divisible by 3 but not by
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17 Jul 2018, 08:01
17 Jul 2018, 08:01
1
amorphous wrote:
If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
A \(\frac{x+1}{2}\)
B \(\frac{x}{7}\)
C \(\frac{x^2}{3}\)
D \(\frac{x^3}{3}\)
E \(\frac{x}{24}\)
source: orbit test prep
Note : x is divisible by 2 not by 3. It means that x is not divisible by 6.
Option E.
x/24
= \(\frac{x}{4*6}\)
Thus option E is never a integer.
Hope it's clear.
