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If [m][fraction]w/x[/fraction][/m] = [m][fraction]2/3[/fract
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21 Apr 2020, 11:36
21 Apr 2020, 11:36
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Question Stats:
95% (01:44) correct
4% (03:32) wrong based on 22 sessions
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If \(\frac{w}{x}\) = \(\frac{2}{3}\) and \(\frac{w}{y}\) = \(\frac{8}{15}\), then \(\frac{(x + y)}{y}\) =
A. \(\frac{4}{5}\)
B. \(\frac{6}{5}\)
C. \(\frac{7}{5}\)
D. \(\frac{8}{5}\)
E. \(\frac{9}{5}\)
Kudos for a correct solution.
A. \(\frac{4}{5}\)
B. \(\frac{6}{5}\)
C. \(\frac{7}{5}\)
D. \(\frac{8}{5}\)
E. \(\frac{9}{5}\)
Kudos for a correct solution.
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If [m][fraction]w/x[/fraction][/m] = [m][fraction]2/3[/fract
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22 Apr 2020, 07:28
22 Apr 2020, 07:28
workout wrote:
If \(\frac{w}{x}\) = \(\frac{2}{3}\) and \(\frac{w}{y}\) = \(\frac{8}{15}\), then \(\frac{(x + y)}{y}\) =
A. \(\frac{4}{5}\)
B. \(\frac{6}{5}\)
C. \(\frac{7}{5}\)
D. \(\frac{8}{5}\)
E. \(\frac{9}{5}\)
Kudos for a correct solution.
A. \(\frac{4}{5}\)
B. \(\frac{6}{5}\)
C. \(\frac{7}{5}\)
D. \(\frac{8}{5}\)
E. \(\frac{9}{5}\)
Kudos for a correct solution.
A quick approach would be to find values of w, x, and y that satisfy both given equations.
Since \(\frac{w}{y}\) = \(\frac{8}{15}\), it could be the case that w = 8 and y = 15
We also know that \(\frac{w}{x}\) = \(\frac{2}{3}\)
Since we already said that w = 8, we can see that x = 12 satisfies the condition that \(\frac{w}{x}\) = \(\frac{2}{3}\), since \(\frac{8}{12}\) = \(\frac{2}{3}\)
So, the values w = 8, y = 15 and x = 12 satisfy both equations.
So....\(\frac{x + y}{y}=\frac{12 + 15}{15}=\frac{27}{15}=\frac{9}{5}\)
Answer: E
Cheers,
Brent
Re: If [m][fraction]w/x[/fraction][/m] = [m][fraction]2/3[/fract
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24 Apr 2020, 03:37
24 Apr 2020, 03:37
if \(\frac{w}{x}\) = \(\frac{2}{3}\)
Then x = \(\frac{3w}{2}\)
and if \(\frac{w}{y}\) = \(\frac{8}{15}\)
then y = \(\frac{15w}{8}\)
x + y = \(\frac{3w}{2}\) + \(\frac{15w}{8}\) = \(\frac{27w}{8}\)
\(\frac{x + y}{y}\) = \(\frac{ (\frac{27w}{8}) }{ (\frac{15w}{8})}\) = \(\frac{9}{5}\)
Answer is E
Then x = \(\frac{3w}{2}\)
and if \(\frac{w}{y}\) = \(\frac{8}{15}\)
then y = \(\frac{15w}{8}\)
x + y = \(\frac{3w}{2}\) + \(\frac{15w}{8}\) = \(\frac{27w}{8}\)
\(\frac{x + y}{y}\) = \(\frac{ (\frac{27w}{8}) }{ (\frac{15w}{8})}\) = \(\frac{9}{5}\)
Answer is E
