GeminiHeat wrote:
If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $56. If $2,000 is the total amount invested, how much is invested at 8 percent?
(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200
I believe there is a mistake in the question. It should be " the annual
interest from the 10 percent investment will exceed the annual
interest from the 8 percent investment by $56".
After this correction, the equations that will end up are x + y =2000 and 0.1x - 0.08y = 56 and solving for y will give 800.
Else as per the original statement, the equations will be x + y =2000 and 1.1x - 1.08y = 56 and none of the choices is the correct.