GreenlightTestPrep wrote:
If x + y = 7 and (x + 1)(y – 1) = 6, what are the possible values of xy?
Indicate all such numbers.
(A) -10
(B) -6
(C) 0
(D) 6
(E) 8
(F) 10
Take x + y = 7, and solve for x to get:
x = 7 - yTake
(x + 1)(y – 1) = 6, and substitute the x-value from the above equation to get:
(7 - y + 1)(y – 1) = 6Simplify:
(8 - y)(y – 1) = 6Use FOIL to expand:
8y - 8 - y² + y = 6Multiply both sides of the equation by -1 to get:
-8y + 8 + y² - y = -6Simplify and set equal to zero:
y² - 9y + 14 = 0Factor:
(y - 2)(y - 7) = 0This means either
y = 2 or
y = 7.
case i: If
y = 2, we can substitute this value into the first equation to get
x + 2 = 7, which means
x = 5. In this case,
xy = (5)(2) = 10case ii: If
y = 7, we can substitute this value into the first equation to get
x + 7 = 7, which means
x = 0. In this case,
xy = (0)(7) = 0Answer: C.F