Carcass wrote:
If xy = 5, yz = 4, zx = 5, and z > 0, what is \(x^3 y^3 z^3\)?
Given:
xy = 5
yz = 4
zx = 5
Note: If z is positive, then we can conclude that y is positive (since yz = 4), and we can conclude that x is positive (since xy = 5)
Multiply all three equations to get: (xy)(yz)(zx) = (5)(4)(5)
Simplify: x²y²z² = 100
Rewrite as:
(xyz)² = 100So, EITHER xyz = 10 OR xyz = -10
Since we've already concluded that x, y and z are all positive, it must be the case that
xyz = 10Now that we know
(xyz)² = 100 and
xyz = 10, we can multiply these equations to get: (
(xyz)²)(
xyz) = (
100)(
10)
Simplify: x³y³z³ = 1000
Answer: 1000