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If y is different from zero which of the following equal y^9/y(y^2)^3
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25 May 2023, 08:43
To simplify the expression, let's start by rewriting it:
\(\frac{y^9}{y(y^2)^3}\)
Since \((y^2)^3\) is equal to \(y^6\), we can substitute it:
\(\frac{y^9}{y(y^6)}\)
Next, we can simplify the fraction by canceling out a y from the numerator and denominator:
\(\frac{y^(9-1)}{y^6}\)
This simplifies to:
\(\frac{y^8}{y^6}\)
When dividing variables with the same base, we subtract the exponents:
\(y^(8-6)\)
\(y^2\)
Therefore, the expression \(\frac{y^9}{y(y^2)^3}\) is equal to \(y^2.\)
So, the correct answer is B. \(y^2.\)