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In a sequence of integers, v, w, x, y, and z, the value of e
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16 Mar 2019, 10:28
16 Mar 2019, 10:28
Expert Reply
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Question Stats:
93% (01:42) correct
6% (00:00) wrong based on 16 sessions
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In a sequence of integers, v, w, x, y, and z, the value of each integer except the first is equal to two more than the product of the previous integer and 2.
If z equals 14, what is the value of w?
A. -1
B. 0
C. 2
D. 6
E. 14
If z equals 14, what is the value of w?
A. -1
B. 0
C. 2
D. 6
E. 14
Re: In a sequence of integers, v, w, x, y, and z, the value of e
[#permalink]
20 Mar 2019, 14:35
20 Mar 2019, 14:35
Expert Reply
We're given the greatest integer, so we'll have to work backwards from there.
Starting at 14, two less than that is 12, and half of that is 6. So y = 6 (now z is equal to two more than the product of y and 2). Alternatively, we can write algebraically:
14 = 2y + 2
Solving for y we get y = 6. Anyways, we can repeat either process. The algebra seems easy at the moment, since the right will remain the same:
6 = 2x + 2
4 = 2x
x = 2
Lastly:
2 = 2w + 2
0 = 2w
w = 0
Starting at 14, two less than that is 12, and half of that is 6. So y = 6 (now z is equal to two more than the product of y and 2). Alternatively, we can write algebraically:
14 = 2y + 2
Solving for y we get y = 6. Anyways, we can repeat either process. The algebra seems easy at the moment, since the right will remain the same:
6 = 2x + 2
4 = 2x
x = 2
Lastly:
2 = 2w + 2
0 = 2w
w = 0
gmatclubot
Re: In a sequence of integers, v, w, x, y, and z, the value of e [#permalink]
20 Mar 2019, 14:35
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