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Re: In the figure, ABCD is a rectangle, and F and E are points o [#permalink]
I am unable to understand the explanation given here. Though I got the correct answer but slightly confused about the method. Would appreciate if someone could solve it
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Re: In the figure, ABCD is a rectangle, and F and E are points o [#permalink]
Carcass wrote:

In the figure, ABCD is a rectangle, and F and E are points on AB and BC, respectively. The area of \(∆DFB\) is 9 and the area of ∆BED is 24. What is the perimeter of the rectangle?

(A) 18

(B) 23

(C) 30

(D) 42

(E) 48



This is a nice question for seeing the different triangles inscribed in shapes. We need to find the dimensions of the rectangle in order to find its perimeter.

So take a look at \(∆DFB\) and \(∆BED\). Notice that the height of \(∆DFB\) is the length \(BC\), and the height of \(∆BED\) is \(DC\).

Now notice that the base of \(∆DFB\) = 2, and we're given that the area of \(∆DFB\) = 9. So with those two pieces of information, we can find the height:

\(\frac{(b*h)}{2} = 9\)
\(\frac{(2*h)}{2} = 9\)

The two's cancel and we get:

\(h = 9\)

So now we have the width of the rectangle, \(BC\), which is 9.

Using the same strategy we used above for \(∆DFB\), \(∆BED\) has a base of 4 and we're given that its area is 24.

\(\frac{(b*h)}{2} = 24\)
\(\frac{(4*h)}{2} = 24\)
\((2*h) = 24\)
\(h = 12\)

And now we know the length of the rectangle, \(DC\), which is 12.

To finish up, we add all the sides together to find the perimeter:

\(9+9+12+12 = 42\)

So D is the answer.
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Re: In the figure, ABCD is a rectangle, and F and E are points o [#permalink]
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