amorphous wrote:
In the xy-coordinate system, the distance between points \((2\sqrt{3}, -\sqrt{2}) and (5\sqrt{3}, 3\sqrt{2}\)) is approximately
A 4.1
B 5.9
C 6.4
D 7.7
E 8.1
Here we can use the formula:- \(\sqrt{(y2 -y1)^2 + (x2 -x1)^2}\)
Here y2= \(5\sqrt{3}\); y1 = \(2\sqrt{3}\)
x2 = \(3\sqrt{2}\) and x1 = \(\sqrt{2}\)
So putting the values in the formula we have:
= \(\sqrt{(5\sqrt{3}-2\sqrt{3})^2+(3\sqrt{2}+\sqrt{2})^2}\)=\(\sqrt{(3\sqrt{3})^2+(4\sqrt{2})^2}\) = \(\sqrt{59}\)
Now we know \(7^2\)=49 and \(8^2\)=64, so 59 should in between \(7<\sqrt{59}<8\).
Therefore only D. gives a possible value