Last visit was: 27 Apr 2024, 14:03 It is currently 27 Apr 2024, 14:03

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 28660
Own Kudos [?]: 33141 [0]
Given Kudos: 25178
Send PM
avatar
Manager
Manager
Joined: 25 Nov 2017
Posts: 51
Own Kudos [?]: 64 [0]
Given Kudos: 0
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2214 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
avatar
Retired Moderator
Joined: 20 Apr 2016
Posts: 1307
Own Kudos [?]: 2214 [0]
Given Kudos: 251
WE:Engineering (Energy and Utilities)
Send PM
Re: In the xy-plane, a circle is centered at the point (-4,3) a [#permalink]
1
Carcass wrote:
In the xy-plane, a circle is centered at the point (-4,3) and passes through the origin. What is the area of the circle?

A. 9π
B. 12π
C. 16π
D. 20π
E. 25π

kudo for the right solution and explanation



Here,

Since the co-ordinates for the centre of the circle = (-4,3)

and it passes through the orgin i.e co ordinates are =(0,0)

NOw the distance from (-4,3) to point (0,0) will give the radius of the circle

Distance between two points (x1,y1) and (x2,y2) in the xy plane = \(\sqrt{{(x2 - x1)^2 + (y2 - y1)^2}}\)

Therefore the distance between (-4,3) and (0,0) = \(\sqrt{{(0 - (-4))^2 + (0 - 3)^2}}\)

=\(\sqrt{25}\) = 5

SInce Area of the circle = \(\pi * (radius)^2\)

= \(\pi * 5^2\)
=\(25\pi\) i. e option E
Target Test Prep Representative
Joined: 09 May 2016
Status:Head GRE Instructor
Affiliations: Target Test Prep
Posts: 180
Own Kudos [?]: 269 [0]
Given Kudos: 114
Location: United States
Send PM
Re: In the xy-plane, a circle is centered at the point (-4,3) a [#permalink]
1
Expert Reply
Carcass wrote:
In the xy-plane, a circle is centered at the point (-4,3) and passes through the origin. What is the area of the circle?

A. 9π
B. 12π
C. 16π
D. 20π
E. 25π


Since the circle is centered at the point (-4,3) and passes through the origin, we see that the radius is the hypotenuse of a triangle, with sides of 3 and 4, so we have a 3-4-5 right triangle with a hypotenuse of 5, which means the radius of the circle is also 5.

Thus, the area of the circle is π(5^2) = 25π,

Answer: E
Prep Club for GRE Bot
[#permalink]
Moderators:
Moderator
1085 posts
GRE Instructor
218 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne