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Line A is perpendicular to the line with the equation
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17 May 2018, 09:40
17 May 2018, 09:40
Expert Reply
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Question Stats:
80% (01:05) correct
20% (00:38) wrong based on 15 sessions
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Line A is perpendicular to the line with the equation \(y= - \frac{1}{5}x\) and the point (3, -10) is on line A. Which of the following is the equation of line A?
A. \(y=- \frac{1}{5} x - \frac{47}{5}\)
B. \(y = \frac{1}{5} x -\frac{53}{5}\)
C. \(y = 5x\)
D. \(y=5x - 5\)
E. \(y=5x - 25\)
A. \(y=- \frac{1}{5} x - \frac{47}{5}\)
B. \(y = \frac{1}{5} x -\frac{53}{5}\)
C. \(y = 5x\)
D. \(y=5x - 5\)
E. \(y=5x - 25\)
Re: Line A is perpendicular to the line with the equation
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03 Aug 2018, 21:25
03 Aug 2018, 21:25
Carcass wrote:
Line A is perpendicular to the line with the equation \(y= - \frac{1}{5}x\) and the point (3, -10) is on line A. Which of the following is the equation of line A?
A. \(y=- \frac{1}{5} x - \frac{47}{5}\)
B. \(y = \frac{1}{5} x -\frac{53}{5}\)
C. \(y = 5x\)
D. \(y=5x - 5\)
E. \(y=5x - 25\)
A. \(y=- \frac{1}{5} x - \frac{47}{5}\)
B. \(y = \frac{1}{5} x -\frac{53}{5}\)
C. \(y = 5x\)
D. \(y=5x - 5\)
E. \(y=5x - 25\)
since line A is perpendicular to the line \(y= - \frac{1}{5}x\),
so slope for line A = 5 (Since the slope of a line perpendicular to a given line is the negative inverse of the slope of the other line)
Now two points of the line a are given as (3 , -10)
Putting them in the line equation
y = mx + c
or -10 = 5 * 3 + c
or c = -25
therefore the equation of line A : y = 5x - 25
Line A is perpendicular to the line with the equation
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21 Apr 2019, 11:25
21 Apr 2019, 11:25
Expert Reply
Line A is perpendicular to the line with the equation \(y = - \frac{1}{5} x\) , and the point (3, -10) is on line A. Which of the following is the equation of line A?
A. \(y = - \frac{1}{5} x -\frac{47}{5}\)
B. \(y = \frac{1}{5} x - \frac{53}{5}\)
C. \(y = 5x\)
D. \(y = 5x - 5\)
E. \(y = 5x - 25\)
A. \(y = - \frac{1}{5} x -\frac{47}{5}\)
B. \(y = \frac{1}{5} x - \frac{53}{5}\)
C. \(y = 5x\)
D. \(y = 5x - 5\)
E. \(y = 5x - 25\)
