Carcass wrote:
ln the coordinate plane, line k passes through the origin and has slope 2. lf points (3,y) and (x,4) are on line k, then x+y =
(A) 3.5
(B) 7
(C) 8
(D) 10
(E) 14
It often helps to write equations for lines in the form
y = mx + b (this is called slope y-intercept form), where m = the slope of the line, and b = the y-intercept of the line.
The question tells us that the line has slope 2. So,
m = 2The question also tells us that the line passes through the origin (0,0). So, the y-intercept is 0, which means b = 0
So, the equation of the line is y = 2x + 0, or just
y = 2xIf the point (3,y) is on the line, then its coordinates must satisfy the equation
y = 2xSo, plug x=3 and y=y into the equation to get y = (2)(3) =
6If the point (x,4) is on the line, then its coordinates must satisfy the equation
y = 2xSo, plug x=x and y=4 into the equation to get 4 = 2x, which means x =
2So, x + y =
2 +
6 = 8
= C
Cheers,
Brent