Re: Mark bought a set of 6 flower pots of different sizes at a total cost
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16 Dec 2022, 23:41
Notice that the prices are are evenly spaced, with common difference of 0.25. Now, for every evenly spaced set (average)=(first+last)/2=(sum)/(number of terms).
Now, if we say that the price of the largest pot is $x, then the price of the smallest pot is $(x-5*0.25) and we'll have that \(\frac{x+x-1.25}{2}=\frac{8.25}{6}\) --> \(2x-1.25=\frac{8.25}{3}\) --> \(x=2\).
Answer: C.