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Mason and Kathy, who both work in the evening
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Updated on: 20 Oct 2018, 00:33
Updated on: 20 Oct 2018, 00:33
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Question Stats:
71% (01:56) correct
28% (01:57) wrong based on 32 sessions
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Mason and Kathy, who both work in the evening wish to arrange for an evening off together. Each evening that Mason is off is followed by 3 evenings that he is a work, and each evening that Kathy is off is followed by 5 evenings that she is at work. If Mason will be off this evening, and Kathy will be off tomorrow evening, how many evenings must pass before they have an evening off together?
(A) 10
(B) 12
(C) 24
(D) 28
(E) So long as they continue this working pattern, they will never have the same evening off.
(A) 10
(B) 12
(C) 24
(D) 28
(E) So long as they continue this working pattern, they will never have the same evening off.
Re: Word Problem!
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19 Oct 2018, 19:50
19 Oct 2018, 19:50
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sarahl wrote:
Mason and Kathy, who both work in the evening wish to arrange for an evening off together.
Each evening that Mason is off is followed by 3 evenings that he is a work, and each evening
that Kathy is off is followed by 5 evenings that she is at work. If Mason will be off this
evening, and Kathy will be off tomorrow evening, how many evenings must pass before they
have an evening off together?
(A) 10
(B) 12
(C) 24
(D) 28
(E) So long as they continue this working pattern, they will never have the same evening off.
Each evening that Mason is off is followed by 3 evenings that he is a work, and each evening
that Kathy is off is followed by 5 evenings that she is at work. If Mason will be off this
evening, and Kathy will be off tomorrow evening, how many evenings must pass before they
have an evening off together?
(A) 10
(B) 12
(C) 24
(D) 28
(E) So long as they continue this working pattern, they will never have the same evening off.
Hi..
There is nothing wrong in it..
Say today is 0th day so , M will be off on 4th day and then on 8th and so on , so multiple of 4 so always EVEN day if today is 0
If today is 0th, tomorrow is 1st and K is off thereafter K is off on each 6th day, so 1,1+6,1+6+6...
Or 1,7,15 thus she is off on ODD days..
So they will never mat h their off days as Even and Odd can never be same
Thus E
