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We have to fill these 6 blanks. Also, the examples show that the digits or letters could be repeated.
Now the last two blanks have a restriction that it can only consist of digits. So, there will be 10 choices for each blank
For, the first four blanks we have 36 choices each(26 letters and 10 digits)
Total possible combinations of passwords = \(36*36*36*36*10*10\)
Now the hacker can check 72 passwords per second so it means he/she can check \(72*60*60\) passwords in an hour.
No of hours to check all the passwords = \(\frac{36*36*36*36*10*10}{72*60*60}\) = 648 hours
OA, CCarcass wrote:
Members of a certain website are required to select passwords that are exactly six characters long. The first four characters may be selected from any of the 26 letters from A to Z (not case-sensitive) or any of the digits 0-9, but the last two characters of the password must be selected from only the digits 0-9. For Instance, abcd45, 8hi976. and 5dog56 are valid passwords. A hacker writes a computer program mat will test every permissible password combination at a rate of 72 passwords per second. How long, IN HOURS, will it take the hacker's program to test every permissible password combination?
A. 18
B. 62
C. 648
D. 1,080
E. 38,880
Kudos for the right answer and explanation