you are right, i missed it

C & E

n^^ = \(n! - n^2\).... n^^ < 0 means \(n!-n^2<0...........n^2>n!......n^2>n(n-1)!.......n>(n-1)!\)
so the number must be greater than the product of numbers less than itself.
3>2*1 but 4 is NOT > 3*2 so values are 1, 2 and 3 but 1 will give us a 0, thus 2 values...
1^^ is 0, so cannot be the answer.
3^^ is negative, so cannot be the answer
so let us check 1^^-2^^ = 0-(2!-2^2)=0-(2-4)=2...answer

B