60% prefer city X and 40% prefer city Y
25% relocated to city X and 75% relocated city Y
If out 75% or 150 relocated to city Y, and the majority prefers city Y, then the highest possible number required is constrained with \(2/3=Y/X\); it's 80 having penchant for city Y with remaining 70 favoring city X. Next, if out of 25% or 50 relocated to city X, all people prefer city X, this is possible as 120 out of 200 like city X, then it will add up to (120-70 already relocated to city Y but prefer city X) 50 having penchant for city X.
Hence, 80+50=130. Answer is
DCarcass wrote:
Of the 200 employees in a certain company, 25 percent will be relocated to City X and the remaining 75 percent will be relocated to City Y. However, 40 percent of the employees prefer City Y and 60 percent prefer City X. What is the highest possible number of employees who will be relocated to the city they prefer?
(A) 65
(B) 100
(C) 115
(D) 130
(E) 135
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) EditionGRE - Math Book