Last visit was: 21 Nov 2024, 12:37 It is currently 21 Nov 2024, 12:37

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 23 Apr 2018
Posts: 26
Own Kudos [?]: 38 [3]
Given Kudos: 0
Send PM
avatar
Supreme Moderator
Joined: 01 Nov 2017
Posts: 371
Own Kudos [?]: 470 [0]
Given Kudos: 0
Send PM
avatar
Manager
Manager
Joined: 23 Oct 2018
Posts: 57
Own Kudos [?]: 0 [0]
Given Kudos: 0
Send PM
Manager
Manager
Joined: 05 Aug 2020
Posts: 101
Own Kudos [?]: 244 [0]
Given Kudos: 14
Send PM
Re: On a certain scale of intensity, each increment of 10 in mag [#permalink]
sarahl wrote:
On a certain scale of intensity, each increment of 10 in magnitude represents a tenfold increase in intensity. On this scale, an intensity corresponding to a magnitude of 165 is how many times an intensity corresponding to a magnitude of 125?


(A) 40
(B) 100
(C) 400
(D) 1,000
(E) 10,000



Putting this into words, we can express it this way:

Let \(x\) by the factor of increase.

So if magnitude goes from 0 to 10, then intensity increases from 0 to 10.
If magnitude goes from 10 to 20, then intensity increases tenfold, so it goes from 10 to 100.
Magnitude increases from 20 to 30, then intensity increases from 100 to 1000.
And so on.

Following this pattern, we can say that:

\(10x => 10^x\), or that \(10x\) corresponds to \(10^x\).

Now we can solve for \(x\) in both magnitude scenarios and find their corresponding intensities:

Magnitude = 165

\(10x = 165\)
\(x = 16.5\)

Which means that:

\(10^x = 10^{16.5}\)


Magnitude = 125

\(10x = 125\)
\(x = 12.5\)

Which means that:

\(10^x = 10^{12.5}\)


Now that we have our intensities, we can compare them:

\(\frac{10^{16.5}}{10^{12.5}} = 10^4 = 10,000\)

So the answer is E
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5030
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: On a certain scale of intensity, each increment of 10 in mag [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: On a certain scale of intensity, each increment of 10 in mag [#permalink]
Moderators:
GRE Instructor
83 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne