The number of people who had driving license $\(=15 \%\)$ of $\(200=30\)$, the number of people who had ticket for parking one or more times $\(=10 \%\)$ of $\(200=20\)$ and the number of people who had neither a license nor a ticket for parking one or more times $\(=78 \%$ of $200=156\)$

Let the number of people who had driving license as well as the ticket for parking one or more times be ' $\(x\)$ '.


As the total number of people is 200 , we get $\((30-\mathrm{x})+\mathrm{x}+(20-\mathrm{x})+156=200\)$ which gives $\(\mathrm{x}=6\)$

So, the number of people who did not have a license but had ticket for parking one or more times $\(=20-x=20-6=14\)$

Hence the answer is (B).