Bunuel wrote:
A container holds 4 quarts of alcohol and 4 quarts of water. How many quarts of water must be added to the container to create a mixture that is 3 parts alcohol to 5 parts water by volume?
A. 4/3
B. 5/3
C. 7/3
D. 8/3
E. 10/3
Here
4quartsofAlcohol4quartsofwaterwe need to add water to above solution to make it equal to =
3partsofAlcohol5partsofwaterLet w= quarts of water required
Total quarts of water = (4 + w)
Therefore we can re write as -
4quartsofAlcohol(4quartsofwater+w) =
3partsofAlcohol5partsofwater(since we need to add w to make the ratio equal to 3/5)
or
4(4+w) =
35or w =
83