Carcass wrote:
If a triangle in the xy-coordinate system has vertices at (– 2, –3), (4, –3) and (28, 7), what is the area of the triangle?
A. 30
B. 36
C. 48
D. 60
E. 65
(-2,-3) and (4,-3) is a straight line parallel to x axis at y=-3. Therefore let's take this as the base..so Base = 4-(-2)=4+2=6..
Now the third vertice is (28,7)..
If we are taking base as parallel to x-axis , the height will be parallel to y-axis.
Therefore height is 7-(-3)=7+3=10
Area will be \(\frac{1}{2}*6*10=30\)
A