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Re: Please Help: Inequality [#permalink]
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Hi,

your approach is fine but is cumbersome and time-consuming.

Thinking logically especially in such case with inequalities is the fastest way to get rid of a question

Reards
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Please Help: Inequality [#permalink]
2
GREhelp wrote:
Thanks so much for the help. I have edited it to include the source. Also I can do a better job naming the topic and ensuring I include the source for all of the questions. Your clarification makes perfect sense and makes it a lot easier. For this question, I tried to solve it a different way.

The steps I took to try to solve this were this:

STEP 1: I multiplied the second inequality by -1 to ensure both have the same sign.
-1 * ( Y - X > 0) which will give you (-Y + X) < 0

STEP 2: LINE UP THE EQUATIONS AND ADD ( I DECIDED TO ADD THE EQUATIONS. This is where I'm struggling, does it matter if we add or subtract? I assumed NOO??)

X + Y < 0
- X - Y < 0
______________
2Y < 0
Y < 0 ANSWER B

( WHY IS THIS INCORRECT? CAN WE SOLVE THIS BY DOING WHAT I DID. The solution suggest that we multiply the top inequality by -1. However, I chose to multiply the bottom and then subtract instead of add. If you were to add you would get

X + Y < 0
+ X - Y < 0
______________
2X < 0
X < 0 ANSWER B


You can add inequalities, but you can't subtract them.
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Re: Please Help: Inequality [#permalink]
2
X + Y < 0
Y - X > 0 ...(2)

Adding the the above inequalties, we get 2X < 0 => X < 0. From inequality (2) we also have Y > X, so the value of Y can be -ve, 0 or +ve, hence the answer is D
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Re: Please Help: Inequality [#permalink]
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