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The cost of an air conditioner is b dollars more than 3 time
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08 Feb 2020, 05:49
08 Feb 2020, 05:49
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The cost of an air conditioner is b dollars more than 3 times the cost of a radio. The total of an air conditioner and a radio is v dollars. Which of the following is the cost of an air conditioner, in dollars?
A. \(\frac{v-b}{4}\)
B. \(\frac{v-b}{3}\)
C. \(\frac{2y+b}{3}\)
D. \(\frac{v+3b}{4}\)
E. \(\frac{3y+b}{4}\)
A. \(\frac{v-b}{4}\)
B. \(\frac{v-b}{3}\)
C. \(\frac{2y+b}{3}\)
D. \(\frac{v+3b}{4}\)
E. \(\frac{3y+b}{4}\)
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Re: The cost of an air conditioner is b dollars more than 3 time
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09 Feb 2020, 09:34
09 Feb 2020, 09:34
GeminiHeat wrote:
The cost of an air conditioner is b dollars more than 3 times the cost of a radio. The total of an air conditioner and a radio is v dollars. Which of the following is the cost of an air conditioner, in dollars?
A. \(\frac{v-b}{4}\)
B. \(\frac{v-b}{3}\)
C. \(\frac{2y+b}{3}\)
D. \(\frac{v+3b}{4}\)
E. \(\frac{3y+b}{4}\)
A. \(\frac{v-b}{4}\)
B. \(\frac{v-b}{3}\)
C. \(\frac{2y+b}{3}\)
D. \(\frac{v+3b}{4}\)
E. \(\frac{3y+b}{4}\)
Let the cost of the air-conditioner be \($a\)
Since the cost of an air conditioner is b dollars more than 3 times the cost of a radio we have:
3 times the cost of a radio is b dollars less than the cost of the air-conditioner
=> Cost of the radio = 1/3 rd of $(a - b) = \($(a-b)/3\)
Thus, total cost of the radio and air-conditioner = \($[a + (a-b)/3] = $(4a-b)/3\)
\(=> (4a-b)/3 = v\)
\(=> 4a-b = 3v\)
\(=> a = (3v + b)/4\)
Answer E
Note: Some of the answer options have the variable \(y\). It should be \(v\) instead
gmatclubot
Re: The cost of an air conditioner is b dollars more than 3 time [#permalink]
09 Feb 2020, 09:34
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