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At a restaurant, all tips are added together to be split amo
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24 Feb 2020, 04:59
24 Feb 2020, 04:59
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At a restaurant, all tips are added together to be split among the employees at the end of a shift. The 4 waiters combined get \(\frac{2}{3}\) of the money, the manager receives \(\frac{1}{4}\) and the busboy receives the remainder. If 1 waiter and the busboy together receive $30, how much money was earned in tips for the entire shift?
A. $90
B. $96
C. $108
D. $120
E. $180
Kudos for the right answer and explanation[/m]
A. $90
B. $96
C. $108
D. $120
E. $180
Kudos for the right answer and explanation[/m]
Re: At a restaurant, all tips are added together to be split amo
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24 Feb 2020, 08:07
24 Feb 2020, 08:07
1
Carcass wrote:
At a restaurant, all tips are added together to be split among the employees at the end of a shift. The 4 waiters combined get \(\frac{2}{3}\) of the money, the manager receives \(\frac{1}{4}\) and the busboy receives the remainder. If 1 waiter and the busboy together receive $30, how much money was earned in tips for the entire shift?
A. $90
B. $96
C. $108
D. $120
E. $180
Kudos for the right answer and explanation[/m]
A. $90
B. $96
C. $108
D. $120
E. $180
Kudos for the right answer and explanation[/m]
Here,
Let the total Tips = X
Now, 4 waiters combined get = \(\frac{2X}{3}\)
and 1 waiter receives = \(\frac{2X}{12}\)
Manager receives = \(\frac{X}{4}\)
the busboy receives = X - (\(\frac{2X}{3} + \frac{X}{4}\)) = \( \frac{X}{12}\)
Since,
1 waiter and the busboy together receive $30
therefore, \(\frac{2X}{12} + \frac{X}{12}\) = $30
or X = $120
gmatclubot
Re: At a restaurant, all tips are added together to be split amo [#permalink]
24 Feb 2020, 08:07
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