k and m are different integers

Currently, k=m, because both k and m equal to 12

$12 \sqrt{12} = k \sqrt{m}$

The variable m is the value under the square root symbol, rather than the value that results when m is placed under the square root symbol.

So if k and m are currently equal, but k must be different than m, how can we increase k or m ?? Factoring the square root

$12 \times \sqrt{12}$

$12 \times \sqrt{4} \times \sqrt{3}$

$12 \times \pm 2 \times \sqrt{3}$

$24 \times \sqrt{3}$ or $-24 \times \sqrt{3}$

Now $k = 24$ or $k = -24$ and $m=3$. Find $k+m$: $24+3=27$ or $-24+3=-21$

B and E are the answers