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Re: If m is an integer such that (-2)^2m = 2^{9 - m}, then m=
[#permalink]
10 Aug 2020, 07:44
1
Farina wrote:
Since base is same so, 2m = 9 - m 2m+m = 9 3m = 9 m = 3
Just wondering about minus sign with 2 in question stem. We have to ignore it?
The base is not the same. The base of the first one is -2 for the LHS and 2 for the RHS. But since the LHS is raised to an even power the negative doesn't matter and we can treat it as 2 instead of -2
Re: If m is an integer such that (-2)^2m = 2^{9 - m}, then m=
[#permalink]
10 Aug 2020, 16:44
chacinluis wrote:
Farina wrote:
Since base is same so, 2m = 9 - m 2m+m = 9 3m = 9 m = 3
Just wondering about minus sign with 2 in question stem. We have to ignore it?
The base is not the same. The base of the first one is -2 for the LHS and 2 for the RHS. But since the LHS is raised to an even power the negative doesn't matter and we can treat it as 2 instead of -2