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Re: Mei is building a garden in the shape of an isosceles triang [#permalink]
Carcass wrote:
To find one of the possible areas, draw out a 10-10-12 triangle.


Attachment:
screenshot.44.png



Notice how one side is 10 and half base is 6. Therefore, the height must be 8

So the area is \(\frac{1}{2} b \times h\)

\(\frac{1}{2} \times 12 \times 8 = 48\)


Why cant we do it like this:
Perimeter = 32 = 10 + 10 + 12
Area = 1/2 b * h
A = 1/2 10 * 10
A = 50

Why do we need perpendicular bisector?
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Re: Mei is building a garden in the shape of an isosceles triang [#permalink]
I agree with you Farina here. I solved the same way like you did. Why Farina's method is incorrect here?
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Re: Mei is building a garden in the shape of an isosceles triang [#permalink]
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Farina used the two side both for one side and the HEIGHT

If one side is 10 another side is 10 as well.

BUT the height cannot be 10 too

More on triangle basic https://gre.myprepclub.com/forum/gre-quant ... tml#p53010

and special triangle https://gre.myprepclub.com/forum/gre-quant ... tml#p53081

Hope this helps
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Re: Mei is building a garden in the shape of an isosceles triang [#permalink]
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