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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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let me find out it, if something is wrong.

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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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\(B=A+(\frac{A}{4})\)

\(B=\frac{5A}{4}\)

\(\frac{A}{B}=\frac{5n}{4n}\)

The TOTAL amount of money must be a multiple of \(9n (5n+4n)\). So 54 and 72 work.
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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B = (5/4 )* A
A+B = A + (5/4) * A = (9/4)* A , now put the values, the answer is 54 and 72 only
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
May someone help me find out what is my mistake ?

B=1.25A
So, the sum is A+1.25A=2.25A
so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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If Beth has 1/4 MORE money than Ari, and each person has an integer number of dollars, which of the following could be the combined value of Beth and Ari's money?

the question is asking about combined value of the 2 people, Total = B+A ==>(1)
B alone = A+1/4A ==> B= 5/4A==>(2)
Substitute b with the first equation ==> Total= 5/4A+A==> Total = 9/4A
the only answers is 54 and 72
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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Asmakan wrote:
May someone help me find out what is my mistake ?

B=1.25A
So, the sum is A+1.25A=2.25A
so the answer must be divided by 2.25 and give us an integer. The correct answer is 72. But wrong.



The correct ans is B and C. Both 54 and 72 when divided by 2.25 gives an integer value.
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If Beth has more money than Ari, and each person has an inte [#permalink]
B = A + A/4 = 5A/4

A + B = A + 5A/4 = 9A/4

Total = 9A/4 = 9/4 * A

The least possible value of A is 4 to make the total value an integer.
So, Total = 9/4 * 4 = 9. The answer will be 9 or the multiples of 9.

Ans: B, C
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Re: If Beth has more money than Ari, and each person has an inte [#permalink]
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