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Re: is a prime number, xy is even, and x > 4y > 0. [#permalink]
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sandy wrote:
\(\sqrt{xy}\) is a prime number, xy is even, and x > 4y > 0.

Quantity A
Quantity B
\(y\)
\(1\)


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.



The only even prime is 2 so xy must be 4 and hence square root of (xy) it has to be 2.

Meaning xy = 4
x = 4/y

4/y > 4y > 0

Divide by 4 and multiplty by y

1 > y^2 > 0

That means y is less than one.

Hence the correct answer choice should B
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is a prime number, xy is even, and x > 4y > 0. [#permalink]
Hi,
Can anyone please help me understand the following:
I understood the part about how y is less than 1 following the reasoning given. But if it were asked what are the possible values of x and y, what would those be?
We know (x)(y) = 4 and y is a fraction less than 1 but greater than 0. Given that x can be any number (integer or fraction) greater than 0, so the possible values for x and corresponding y to yield xy = 4 is infinite, right?

Please correct me if I am wrong.
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is a prime number, xy is even, and x > 4y > 0. [#permalink]
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Yeah, right.

As long as \(xy = 4\), there will be many values (integers, fractions). Hence, to remove obscurity, some conditions will be mentioned.
17221058 wrote:
Hi,
Can anyone please help me understand the following:
I understood the part about how y is less than 1 following the reasoning given. But if it were asked what are the possible values of x and y, what would those be?
We know (x)(y) = 4 and y is a fraction less than 1 but greater than 0. Given that x can be any number (integer or fraction) greater than 0, so the possible values for x and corresponding y to yield xy = 4 is infinite, right?

Please correct me if I am wrong.
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