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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Presently, Fred is 4 times as old as Gary.
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26 Jun 2018, 06:42
26 Jun 2018, 06:42
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Question Stats:
93% (01:04) correct
6% (01:28) wrong based on 32 sessions
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Presently, Fred is 4 times as old as Gary. In 10 years, Fred will be 3 times as old as Gary. How old (in years) will Fred be in 3 years?
Show: ::
83
Re: Presently, Fred is 4 times as old as Gary.
[#permalink]
26 Jun 2018, 10:49
26 Jun 2018, 10:49
1
GreenlightTestPrep wrote:
Presently, Fred is 4 times as old as Gary. In 10 years, Fred will be 3 times as old as Gary. How old (in years) will Fred be in 3 years?
Show: ::
83
Here ;
Present age of Fred be = F years and Gary's = G years
therefore;
F = 4G
In 10 years;
F+10 = 3(G +10)
or G = 20 years which is Gray's present age
Therefore F = 20 * 4 = 80 years which is the present age (since we know F = 4G)
In 3years Fred will be = 80 +3 = 83 years
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Presently, Fred is 4 times as old as Gary.
[#permalink]
30 Jun 2018, 06:38
30 Jun 2018, 06:38
GreenlightTestPrep wrote:
Presently, Fred is 4 times as old as Gary. In 10 years, Fred will be 3 times as old as Gary. How old (in years) will Fred be in 3 years?
Show: ::
83
Let's solve the question using 2 variables
Let F = Fred's PRESENT age
Let G = Gary's PRESENT age
Presently, Fred is 4 times as old as Gary
In other words, F = 4G
In 10 years, Fred will be 3 times as old as Gary.
IN 10 YEARS, Fred's age = F + 10
IN 10 YEARS, Gary's age = G + 10
If Fred will be 3 times as old as Gary, we can write: F + 10 = 3(G + 10)
Expand: F + 10 = 3G + 30
Rearrange to get: F = 3G + 20
We now have the following system:
F = 4G
F = 3G + 20
Since both equations set equal to F, we can write: 4G = 3G + 20
When we solve this, we get G = 20
Since F = 4G, we can now say that F = 4(20) = 80
In other words, Fred's PRESENT age is 80
So, IN 3 YEARS, Fred's age will be 83
Answer: 83
Cheers,
Brent
