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Rachel, David, and Kristen decide to pool their money to buy
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27 Jan 2020, 03:35
27 Jan 2020, 03:35
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Rachel, David, and Kristen decide to pool their money to buy a video game system. David contributes 4 dollars more than twice what Kristen does, and Kristen contributes 3 dollars less than Rachel does. If Rachel contributes r dollars, then, how much does David contribute in terms of r ?
A. \(\frac{r-7}{2}\)
B. \(\frac{r-2}{2}\)
C. \(\frac{2r+7}{2}\)
D. \(2r-2\)
E. \(2r+7\)
Kudos for the right answer and explanation
A. \(\frac{r-7}{2}\)
B. \(\frac{r-2}{2}\)
C. \(\frac{2r+7}{2}\)
D. \(2r-2\)
E. \(2r+7\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: Rachel, David, and Kristen decide to pool their money to buy
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27 Jan 2020, 07:02
27 Jan 2020, 07:02
1
Carcass wrote:
Rachel, David, and Kristen decide to pool their money to buy a video game system. David contributes 4 dollars more than twice what Kristen does, and Kristen contributes 3 dollars less than Rachel does. If Rachel contributes r dollars, then, how much does David contribute in terms of r ?
A. \(\frac{r-7}{2}\)
B. \(\frac{r-2}{2}\)
C. \(\frac{2r+7}{2}\)
D. \(2r-2\)
E. \(2r+7\)
Kudos for the right answer and explanation
A. \(\frac{r-7}{2}\)
B. \(\frac{r-2}{2}\)
C. \(\frac{2r+7}{2}\)
D. \(2r-2\)
E. \(2r+7\)
Kudos for the right answer and explanation
GIVEN: Rachel contributes \(r\) dollars
GIVEN: Kristen contributes \(3\) dollars less than Rachel does.
So, \(r-3\) = the amount that Kristen contributed
GIVEN: David contributes \(4\) dollars more than twice what Kristen does
\(2(r-3)\) = TWICE the amount that Kristen contributed
So, \(2(r-3) + 4\) = 4 dollars MORE than twice the amount that Kristen contributed
Take \(2(r-3) + 4\), and expand and simplify it to get \(2r-2\)
Answer: D
Cheers,
Brent
Re: Rachel, David, and Kristen decide to pool their money to buy
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12 Aug 2020, 08:46
12 Aug 2020, 08:46
D if I'm not mistaken.
