Yes that can be done as well.
Similarly,
As this is a large no, take the last two \(21\) as the mean of five nos, so total will be \(105\).
Now new no \(987\), but take last two \(87\) and add them to \(105\), so the sum will be \(192\).
When divided by \(6\), the answer will be \(32\). Last two digits of the correct answer.
aishumurali wrote:
HI , in this method i subtracted both the mean and new entity by 918,273,645 . I got the mean as 321 and the entity as 987 . I then multiplied 321 * 5 and got the answer as 1605 and added 987 to it and then divided by 6 and got the answer as 432 which is the last digit of option C .
Is my method correct?
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