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Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Set A currently has five numbers, and its mean is 918,273,645,321. If
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29 Jul 2021, 10:55
29 Jul 2021, 10:55
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Question Stats:
84% (01:32) correct
15% (02:10) wrong based on 13 sessions
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Set A currently has five numbers, and its mean is 918,273,645,321. If a new number 918,273,645,987 is added to the set A, what will be a new mean of the set A?
(A) 918,273,645,421
(B) 918,273,645,431
(C) 918,273,645,432
(D) 918,273,645,441
(E) 918,273,645,442
Please do not use excell, or online calculator. This question is supposed to test not your calculator skills, GRE calculator will not fit this number BTW
(A) 918,273,645,421
(B) 918,273,645,431
(C) 918,273,645,432
(D) 918,273,645,441
(E) 918,273,645,442
Please do not use excell, or online calculator. This question is supposed to test not your calculator skills, GRE calculator will not fit this number BTW
Re: Set A currently has five numbers, and its mean is 918,273,645,321. If
[#permalink]
29 Jul 2021, 12:32
29 Jul 2021, 12:32
1
Honestly I cannot explain what I did but I just saw the last 3 digits were different. So I subtracted the two numbers and got 666. Then later just divided that number by 6 coz the addition of new number makes the number of entries 6. I got the answer 111. Now I added 111 to the number which was initially the mean of 5 numbers. And Arrived at option C and to my surprise it turns out to be Correct. So despite solving it please explain what I really should have done and what is the real method for solving such sums ?
Retired Moderator
Joined: 19 Nov 2020
Posts: 326
Given Kudos: 64
GRE 1: Q160 V152
Re: Set A currently has five numbers, and its mean is 918,273,645,321. If
[#permalink]
29 Jul 2021, 12:50
29 Jul 2021, 12:50
iampratikthorat wrote:
Honestly I cannot explain what I did but I just saw the last 3 digits were different. So I subtracted the two numbers and got 666. Then later just divided that number by 6 coz the addition of new number makes the number of entries 6. I got the answer 111. Now I added 111 to the number which was initially the mean of 5 numbers. And Arrived at option C and to my surprise it turns out to be Correct. So despite solving it please explain what I really should have done and what is the real method for solving such sums ?
Your answer and logic are correct.
