hathunguyen254 wrote:
GreenlightTestPrep wrote:
KarunMendiratta wrote:
Set A includes consecutive integers from -10 to 10 (inclusive). 20 integers are randomly selected (repetition is allowed) from the set.
Quantity A |
Quantity B |
Least possible value of the product of all selected integers |
0 |
A. Quantity A is greater
B. Quantity B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given
Choose nineteen 10's and one -10
So, the product =
[(10)^19][-10]Notice that
[(10)^19] is POSITIVE, which means
[(10)^19][-10] is NEGATIVE.
So,
[(10)^19][-10] =
[(10)^19][-1][10]= -(10)^20
= E
So, we have:
QUANTITY A: -(10)^20
QUANTITY B: 0
Answer: B
I'm a bit confused when it says "consecutive integers". How can the set contains nineteen 10s and one (-10) if they are consecutive integers?
Hi, I think you mis-undertood the question.
The question says,
20 integers are randomly selected (repetition is allowed)Set A has integers from -10 to 10 only (counted once), but the question wants us to select 20 integers with repetition allowed.
So, we can select -10, -10, -10, ......... (20 times)
As per the question,
The product has to be least. So, we will pick -10 (19 times) and greatest positive integer to make it least i.e. +10
So, Least product = \(-(10)^{19}(10) = -(10)^{20}\)