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Set X contains 10 consecutive integers. If the sum of the 5 smallest m
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25 Jun 2022, 04:04
25 Jun 2022, 04:04
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Set X contains 10 consecutive integers. If the sum of the 5 smallest members of Set X is 265, then what is the sum of the 5 largest members of Set X?
(A) 290
(B) 285
(C) 280
(D) 275
(E) 270
(A) 290
(B) 285
(C) 280
(D) 275
(E) 270
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
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Re: Set X contains 10 consecutive integers. If the sum of the 5 smallest m
[#permalink]
25 Jun 2022, 06:35
25 Jun 2022, 06:35
1
Carcass wrote:
Set X contains 10 consecutive integers. If the sum of the 5 smallest members of Set X is 265, then what is the sum of the 5 largest members of Set X?
(A) 290
(B) 285
(C) 280
(D) 275
(E) 270
(A) 290
(B) 285
(C) 280
(D) 275
(E) 270
Part of the project: GRE QCQ & PS 3 Questions Every One DAILY Challenge - (2022)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
GRE Math Essentials for a TOP Quant Score - Q170!!! (2021)
GRE Geometry Formulas for a Q170
GRE - Math Book
-------ASIDE-------------------------------------------
Notice that we can write the first 10 consecutive integers as follows:
1, 2, 3, 4, 5, (1 + 5), (2 + 5), (3 + 5), (4 + 5), (5 + 5)
So, the sum of the first 5 integers = 1 + 2 + 3 + 4 + 5
The sum of the last 5 integers = (1 + 5) + (2 + 5) + (3 + 5) + (4 + 5) + (5 + 5)
= 1 + 2 + 3 + 4 + 5 + 5 + 5 + 5 + 5 + 5
= 1 + 2 + 3 + 4 + 5 + 25
In other words, the sum of the last 5 numbers = (the sum of the first 5 numbers) + 25
--------NOW ONTO THE QUESTION-----------------
The same approach can be applied to the given information.
The sum of the last 5 numbers = (the sum of the first 5 numbers) + 25
= 265 + 25
= 290
Answer: A
gmatclubot
Re: Set X contains 10 consecutive integers. If the sum of the 5 smallest m [#permalink]
25 Jun 2022, 06:35
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