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The ages of three people are such that the age of one person is twice
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06 Apr 2021, 02:31
06 Apr 2021, 02:31
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Question Stats:
72% (01:12) correct
27% (02:02) wrong based on 22 sessions
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The ages of three people are such that the age of one person is twice the age of the second person and three times the age of the third person. If the sum of the ages of the three people is 33, then the age of the youngest person is
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
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Re: The ages of three people are such that the age of one person is twice
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06 Apr 2021, 05:32
06 Apr 2021, 05:32
1
Carcass wrote:
The ages of three people are such that the age of one person is twice the age of the second person and three times the age of the third person. If the sum of the ages of the three people is 33, then the age of the youngest person is
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
(A) 3
(B) 6
(C) 9
(D) 11
(E) 18
Kudos for the right answer and explanation
Question part of the project GRE Quantitative Reasoning Daily Challenge - (2021) EDITION
GRE - Math Book
There are a few ways to solve this question.
Let x = age of first person mentioned in the question
The age of one person is twice the age of the second person and three times the age of the third person
We're saying that x = the age of the first person.
Since this person is TWICE as old as the second person, we can say that the age of the second person is HALF the age of the first person.
So, x/2 = age of second person.
Likewise, x/3 = age of third person
The sum of the ages of the three people is 33
So, x + x/2 + x/3 = 33
To eliminate the fractions, multiply both sides by 6 to get: 6x + 3x + 2x = (33)(6) [in a second, you'll see why I didn't bother to evaluate 33 times 6]
Simplify: 11x = (33)(6)
Divide both sides by 11 to get: x = (33)(6)/11 = (3)(6) = 18
Be careful. The question asks for the age of the YOUNGEST person.
The ages were assigned as x, x/2 and x/3
So, if x = 18, then the x/2 = 18/2 = 9, and x/3 = 18/3 = 6
So, the three ages are 18, 9 and 6
So, the youngest person is 6 years old.
Answer: B
Re: The ages of three people are such that the age of one person is twice
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06 Apr 2021, 05:48
06 Apr 2021, 05:48
1
x+x/2+x/3=33
x=18
Answer - B
x=18
Answer - B
