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The average (arithmetic mean) of the even integers from 100 to 200, in
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19 Aug 2021, 05:16
19 Aug 2021, 05:16
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Question Stats:
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The average (arithmetic mean) of the even integers from 100 to 200, inclusive, is how much greater than the average of the odd integers from 75 to 125, inclusive?
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
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Re: The average (arithmetic mean) of the even integers from 100 to 200, in
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19 Aug 2021, 07:58
19 Aug 2021, 07:58
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Carcass wrote:
The average (arithmetic mean) of the even integers from 100 to 200, inclusive, is how much greater than the average of the odd integers from 75 to 125, inclusive?
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
Average in case of consecutive integers = \(\frac{Last + First}{2}\)
Average of given consecutive even integers = \(\frac{200 + 100}{2} = 150\)
Average of given consecutive odd integers = \(\frac{125 + 75}{2} = 100\)
Difference = \(150 - 100 = 50\)
Hence, option D
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Re: The average (arithmetic mean) of the even integers from 100 to 200, in
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11 Nov 2021, 12:48
11 Nov 2021, 12:48
Carcass wrote:
The average (arithmetic mean) of the even integers from 100 to 200, inclusive, is how much greater than the average of the odd integers from 75 to 125, inclusive?
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
(A) 10
(B) 25
(C) 45
(D) 50
(E) 75
Kudos for the right answer and explanation
Question part of the project GRE Quant/Math Extreme Challenge Daily (2021) Edition
GRE - Math Book
Key property: If a set of numbers are equally spaced, then the average of the set equals the average of the smallest and largest numbers.
So, the average of the even integers from \(100\) to \(200 \)\(= \frac{100+200}{2}=\frac{300}{2}=150\)
And the average of the odd integers from \(75\) to \(125\) \(= \frac{75+125}{2}=\frac{200}{2}=100\)
Difference \(= 150-100=50\)
Answer: D
