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Re: The average (arithmetic mean) of x and x equals [#permalink]
1
Answer should be D, I don't understand how it could be A. if x is less than 0 (say -1) then -1+(-1)= -2/2= -1. This discredits the rule that x will = 0 if its less than or equal to 0.
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Re: The average (arithmetic mean) of x and x equals [#permalink]
can someone pls explain? I got D as the answer. How can X be 0 when it takes a minus value?
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Re: The average (arithmetic mean) of x and x equals [#permalink]
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Carcass wrote:
The average (arithmetic mean) of x and x equals

(A) x if x > 0, and equals 0 if x ≤ 0
(B) -x if x < 0, and equals 0 if x ≥ 0
(C) 0, regardless of the value of x
(D) x, regardless of the value of x
(E) |x|, regardless of the value of x

Kudos for the right answer and explanation


Approach #1: Apply the average formula
Average \(= \frac{x + x}{2}= \frac{2x}{2}=x\)
Notice that x can be any value
Answer: D

Approach #2: Eliminate 4 answer choices
Try \(x = -1\)
Average \(= \frac{(-1) + (-1)}{2}= \frac{-2}{2}=-1\)
This means we can:
- eliminate answer choice A, since it says the average must equal 0 if x ≤ 0
- eliminate answer choice B, since it says the average must -(-1) (i.e., 1)
- eliminate answer choice C, since it says the average must equal 0
- eliminate answer choice D, since it says the average must equal |-1| (i.e., 1)
By the process of elimination, the correct answer must be D.

NOTE: I have change the correct answer to D

Cheers,
Brent
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Re: The average (arithmetic mean) of x and x equals [#permalink]
GreenlightTestPrep

Thank u sir.
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Re: The average (arithmetic mean) of x and x equals [#permalink]
Theory

    ➡ Average = Sum of all the Values / Total Number of Values

The average (arithmetic mean) of x and x

Average = \(\frac{Sum}{2}\) = \(\frac{x + x}{2}\) = x

So, Answer will be D.
Hope it helps!

Watch the following video to Learn the Basics of Statistics

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Re: The average (arithmetic mean) of x and x equals [#permalink]
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