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The discrimant of
[#permalink]
01 Sep 2021, 10:06
01 Sep 2021, 10:06
Expert Reply
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Question Stats:
71% (00:33) correct
28% (01:31) wrong based on 14 sessions
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Quantity A |
Quantity B |
The discrimant of \(x^2+x+1=0\) |
The discrimant of \(x^2-x+1=0\) |
A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
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Re: The discrimant of
[#permalink]
04 Sep 2021, 08:08
04 Sep 2021, 08:08
1
Theory: Discriminant of a Quadratic equation a\(x^2\) + bx + c = 0 is \(b^2\) - 4ac
Quantity A: The Discriminant of \(x^2+x+1=0\)
Comparing it with a\(x^2\) + bx + c = 0 we get
a=1, b=1, c=1
=> Discriminant = \(b^2\) - 4ac = \(1^2\) - 4*1*1 = 1-4 = -3
Quantity B: The Discriminant of \(x^2-x+1=0\)
Comparing it with a\(x^2\) + bx + c = 0 we get
a=1, b=-1, c=1
=> Discriminant = \(b^2\) - 4ac = \((-1)^2\) - 4*1*1 = 1-4 = -3
=> Quantity A = Quantity B = -3
So, Answer will be C
Hope it helps!
Quantity A: The Discriminant of \(x^2+x+1=0\)
Comparing it with a\(x^2\) + bx + c = 0 we get
a=1, b=1, c=1
=> Discriminant = \(b^2\) - 4ac = \(1^2\) - 4*1*1 = 1-4 = -3
Quantity B: The Discriminant of \(x^2-x+1=0\)
Comparing it with a\(x^2\) + bx + c = 0 we get
a=1, b=-1, c=1
=> Discriminant = \(b^2\) - 4ac = \((-1)^2\) - 4*1*1 = 1-4 = -3
=> Quantity A = Quantity B = -3
So, Answer will be C
Hope it helps!
gmatclubot
Re: The discrimant of [#permalink]
04 Sep 2021, 08:08
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